<p>我正在尝试输入条件渲染，但是它报错了：<code>Element implicitly has an 'any' type because expression of type 'number' can't be used to index type 'types'. No index signature with a parameter of type 'number' was found on type 'types'.</code> 当所有内容都是"any"时，渲染是有效的。</p> <pre class="brush:php;toolbar:false;">interface types { '0': JSX.Element; '1': JSX.Element; '2': JSX.Element; } export default function Economy(props: any) { const [step, setStep] = useState(0) const render = () =&gt; { const component: types = { '0': &lt;Home /&gt;, '1': &lt;Create /&gt;, '2': &lt;Detail /&gt;, } return component[step] } return ( {render()} )</pre> <p>有人能帮我理解如何为这个条件渲染添加类型吗？</p> <p>我需要理解如何为这个条件渲染添加类型</p>

interface types {
  '0': JSX.Element;
  '1': JSX.Element;
  '2': JSX.Element;
}

export default function Economy(props: any) {
  const [step, setStep] = useState<keyof types>("0")

  const render = () => {
    const component: types = {
      '0': <Home />,
      '1': <Create />,
      '2': <Detail />,
    }
    return component[step]
  }
return (
   {render()}
)

const [step, setStep] = useState<keyof types>(0)

interface types {
  0: JSX.Element;
  1: JSX.Element;
  2: JSX.Element;
}
 const component: types = {
      0: <Home />,
      1: <Create />,
      2: <Detail />,
    }
 return component[step] // 没有错误