我目前通过调用异步函数并将其与.then()链接来处理我的承诺。但我希望有一种更易读的方法。
我目前的可行方法是:
const apiCall = async() => {
const response = await axios.get("URL");
return response;
}
apiCall().then(res => {
console.log(res.data);
});
我希望我的代码看起来像:
const apiCall = () => {
const response = axios.get("URL);
return response;
}
const fetchData = async() => {
const response = await apiCall();
return response.data;
}
console.log(fetchData()); Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号
如何
const apiCall = async() => { const { data } = await axios.get("URL"); return data; }