摘要:–创建图书表create table book(no varchar2(64),name varchar2(10),author varchar2(10),category varchar2(10));–插入数据–insert into 表名(各个列明)–values(各列对应的值)insert into book (no,name,author,category)values(‘001’,‘简爱
–创建图书表
create table book
(
no varchar2(64),
name varchar2(10),
author varchar2(10),
category varchar2(10)
);
–插入数据–insert into 表名(各个列明)
–values(各列对应的值)
insert into book (no,name,author,category)values(‘001’,‘简爱’,‘夏洛蒂’,‘文学小说’);
insert into book (no,name,author,category)values(‘002’,‘平凡的世界’,‘路遥’,‘文学小说’);
insert into book (no,name,author,category)values(‘003’,‘物种起源’,‘达尔文’,‘生物学’);
insert into book (no,name,author,category)values(‘004’,‘意林’,‘文学联合会’,‘杂志’);
---------------------
作者:wangmeili1231
来源:CSDN
原文:https://blog.csdn.net/wangmeili1231/article/details/88218535
版权声明:本文为博主原创文章,转载请附上博文链接!
						批改老师:天蓬老师批改时间:2019-07-05 14:45:02		
						
老师总结:这种复制粘贴的作业 , 你发布前至少要看一眼吧, 如果是提交给客户的代码, 你还指望能收到尾款吗?
--------------------- 
作者:wangmeili1231 
来源:CSDN 
原文:https://blog.csdn.net/wangmeili1231/article/details/88218535 
版权声明:本文为博主原创文章,转载请附上博文链接!					
 
                 
 
 
  
            