PHP开发企业网站教程之添加新闻资讯
点击添加按钮 跳转到addne.php 页面
我们来看下 addne.php 代码:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>添加新闻资讯</title>
<style type="text/css">
.ipt{width:180px;height:30px;border-radius:5px;
outline:none;border:1px solid #eee;box-sizing:border-box;padding-left:15px;}
.txt{width:250px;height:200px;}
.sub{width:50px;height:20px;border:1px solid #eee;background:#eee;color:#ff7575;}
</style>
</head>
<body>
<form method="post" action="addnews.php">
标题:<input type="text" name="title" class="ipt">
</br></br>
内容:<textarea cols="50" rows="5" name="content" class="txt"></textarea></br></br>
<select name="type">
<option value="0">公司公告</option>
<option value="1">公司新闻</option>
</select>
</br></br>
<input type="submit" value="添加" class="sub">
</form>
</body>
</html>看如上代码:表单提交addnews.php 页面
下面我们来看以下addnews.php页面的代码:
<?php
//添加新闻资讯
require_once('conn.php');
$title=$_POST['title'];
$content = $_POST['content'];
$type = $_POST['type'];
$newtime = time();
$sql = "insert into `news`(title,type,content,newtime) values('$title','$type','$content','$newtime')";
$res = mysql_query($sql);
if($res){
echo "<script>alert('添加新闻成功');location.href='news.php';</script>";
}else{
echo "<script>alert('添加新闻失败');location.href='news.php';</script>";
}
?>获取表单信息,然后添加到数据库 表中,然后对其进行判断,是否添加成功
